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الكلية كلية العلوم للبنات
القسم قسم فيزياء الليزر
المرحلة 2
أستاذ المادة محمد حمزة خضير المعموري
13/11/2018 18:22:09
1 Introduction and Ray Optics Optics is the study of light and its interaction with matter. Light is visible electromagnetic radiation, which transports energy and momentum (linear and angular) from source to detector. Photonics includes the generation, transmission, modulation, amplification, frequency conversion and detection of light. ,Methods of studying light, in historical order are: -ray optics -wave optics -electromagnetic optics -photon optics (E & M fields are wavefunctions of photons). In this course, we will focus on electromagnetic optics. Maxwell’s equations give accurate descriptions of most optical phenomena. However, for pedagogical reasons, we begin, with ray optics. 1.1 Ray Optics Ray optics is the simplest theory of light. Rays travel in optical media according to a set of geometrical rules; hence ray optics is also called geometrical optics. Ray optics is an approximate theory, but describes accurately a variety of phenomena. Ray optics is concerned with the locations and directions of light rays, which carry photons and light energy (They also carry momentum, but the direction of the momentum may be different from the ray direction). It is useful in describing image formation, the guiding of light, and energy transport. Optical systems are often centered around an axis, called the optical axis. If rays are nearly parallel to such an axis, they are called paraxial rays. The study of paraxial rays is called paraxial optics. 1.2 Postulates of Ray Optics 1. Light travels in the form of rays (can think of rays as photon currents). Rays are emitted by light sources, and can be observed by light detectors. 2. An optical medium (through which rays propagate) is characterized by a real scalar quantity n 1, called the refractive index. The speed of light in vacuum is c = 3 × 108m/s.The speed of light in a medium is v = c/n; this is the definition of the refractive index. The time taken by light to cover a distance d is t = nd/c; it is proportional to nd, which is called the optical path length. 1 3. In an inhomogeneous medium, the refractive index n(r) varies with position; hence the optical path length OPL between two points A and B is OPL = B A n(r)ds where ds is an element of length along the path. The time t taken by light to go from A to B is t = OPL/c. 4. FermatsPrinciple Light rays between the points A and B follow a path such that the time of travel, relative to neighboring paths, is an extremum (minimum). This means that the variation in the travel time, or, equivalently, in the optical path lenght, is zero. That is,
B A n(r)ds = 0 (1) Usually, the extremum is a minimum; then light rays travel along the path of least time. If there are many paths with the minimum time, then light rays travel along all of these simultaneously. Why should Fermat’s principle work? Were is the physics? (Fermat’s principle is the main principle of quantum electrodynamics! It is a consequence of Huygen’s principle: waves with extremal paths contribute the most due to constructive interference.) 1.2.1 Propagation in a homogeneous medium In a homogeneous medium, the refractive index n is the same everywhere, so is the speed of light v. Therefore the optical path length of least time is the shortest one - that is, a straight line. Proof: Suppose the path taken by light is along the curve described by y(x). The optical path length is OPL = B A nds = n B A ds (2) We want to minimize the OPL. Suppose y0(x) is the shortest path. Then we must have that any other path is longer. Consider the path y(x) = y0(x)+(x) , 2 where (x) is small. We note that ds =
dx2 + dy2 = dx
1 + ( dy dx )2 = dx
1 + y2(x) (3) Since y(x) = y
0(x) + (x), we can write ds = dx
1 + y2 0 + 2y o + 2 (4) If is also small, we have, approximately ds = dx
1 + y 0 2
1 + 2y o 1 + y 0 2 dx
1 + y 0 2 + dx y 0 1 + y 0 2 (5) and the optical path length which we varied, OPLv is OPLv = n B A (
1 + y 0 2 + y 0 1 + y 0 2 )dx (6) Now we said that y0(x) is the shortest path, that is, the shortest opical path length OPLS OPLS = n B A (
1 + y 0 2)dx (7) is a minimum. This means that OPLv cannot be less than OPLS. If we could choose freely, then we could argue that the coefficient of must be equal to zero, otherwise, by choosing appopriately, we chould make OPLv less than OPLS, in violation of our original assumption. However, we cannot choose freely, since we have the constraint that (x) = 0 at the end points. (This is because all paths must go through the end points, and since y0(x) certainly does, (x) must vanish there.) We therefore recall that B A udv = uv|B A ? B A vdu (8) and write B A y 0 1 + y 0 2 dx = y 0 1 + y 0 2 |B A ? B A
d dx ( y 0 1 + y 0 2 ) (9) Since vanishes at the end points, the first term on the rhs is zero, and we have A OPLv = n B A (
1 + y 0 2 ? n B A
d dx ( y 0 1 + y 0 2 ) (10) 3
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