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الكلية كلية الهندسة
القسم الهندسة الميكانيكية
المرحلة 1
أستاذ المادة احمد كاظم حسين الحميري
15/12/2016 16:35:50
Definition 1 Hyperbolic Functions sinh x = ex?e?x 2 cosh x = ex+e?x 2 tanh x = sinh x cosh x coth x = cosh x sinh x sech x = 1 cosh x csch x = 1 sinh x The hyperbolic functions are closely related to the trigonometric functions. The first example of this follows from the identity cosh2 x ? sinh2 x = 1 We can verify this from the definitions, cosh2 x ? sinh2 x = e2x + e?2x + 2 4 ? e2x + e?2x ? 2 4 = 1 Just like x = cos t and y = sin t gives a parametric representation for a circle, the above formula implies that x = cosh t and y = sinh t gives a parametric representation for the right branch of the hyperbola x2?y2 = 1. Just like their trigonometric counterparts, sinh x, tanh x, csch x, and coth x are odd functions, cosh x and sech x are even functions. This is also easily verified from the definitions. Definition 2 Derivatives of Hyperbolic Functions Dx sinh x = cosh x Dx cosh x = sinh x Dx tanh x = sech2 x Dx coth x = ?csch2 x Dx sech x = ?sech x tanh x Dx csch x = ?csch x coth x Another way the trigonometric and hyperbolic functions are connected concerns differential equations. The functions sin x and cos x are solutions to the differential equation y00 + y = 0, while sinh x and cosh x are solutions to the differential equation y00 ? y = 0. Example 1 Find Dx cosh (tan x). Solution Dx cosh (tan x) = sinh (tan x)Dx (tan x) = sec2 x · sinh (tan x) 1 Example 2 Find R coth x dx. Solution Let u = sinh x, so that du = cosh x dx. Z coth x dx = R cosh x sinh x dx = Z 1 u du = ln |u| + C = ln |sinh x| + C Since hyperbolic sine and hyperbolic tangent have positive derivatives, they are increasing functions and automatically have inverses. To obtain inverses for hyperbolic cosine and hyperbolic secant, we restrict their domains to x 0. Thus, x = sinh?1 y , y = sinh x x = cosh?1 y , y = cosh x and x 0 x = tanh?1 y , y = tanh x x = sech?1 y , y = sech x and x 0 Since the hyperbolic functions are defined in terms of exponentials, it seems likely that the inverse hyperbolic functions can be defined in terms of the natural log, and indeed this is so as long as we make some necessary domain restrictions. sinh?1 x = ln ?? x + p x2 + 1
cosh?1 x = ln ?? x + p x2 ? 1
, x 1 tanh?1 x = 1 2 ln 1+x 1?x , ?
المادة المعروضة اعلاه هي مدخل الى المحاضرة المرفوعة بواسطة استاذ(ة) المادة . وقد تبدو لك غير متكاملة . حيث يضع استاذ المادة في بعض الاحيان فقط الجزء الاول من المحاضرة من اجل الاطلاع على ما ستقوم بتحميله لاحقا . في نظام التعليم الالكتروني نوفر هذه الخدمة لكي نبقيك على اطلاع حول محتوى الملف الذي ستقوم بتحميله .
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