Forces parallel to the area resisting the force cause shearing stress. It differs to tensile
and compressive stresses, which are caused by forces perpendicular to the area on
which they act. Shearing stress is also known as tangential stress.
where V is the resultant shearing force which passes which passes through the centroid
of the area A being sheared.
SOLVED PROBLEMS IN SHEARING STRESS
Problem 115
What force is required to punch a 20-mm-diameter hole in a plate that is 25 mm thick?
The shear strength is 350 MN/m2
As in Fig. 1-11c, a hole is to be punched out of a plate having a shearing strength of 40
ksi. The compressive stress in the punch is limited to 50 ksi. (a) Compute the maximum
thickness of plate in which a hole 2.5 inches in diameter can be punched. (b) If the
plate is 0.25 inch thick, determine the diameter of the smallest hole that can be
punched.
Find the smallest diameter bolt that can be used in the clevis shown in Fig. 1-11b if P =
400 kN. The shearing strength of the bolt is 300 MPa.
Solution 117
Problem 118
A 200-mm-diameter pulley is prevented from rotating relative to 60-mm-diameter shaft
by a 70-mm-long key, as shown in Fig. P-118. If a torque T = 2.2 kN·m is applied to the
shaft, determine the width b if the
allowable shearing stress in the key is 60 MPa.
المادة المعروضة اعلاه هي مدخل الى المحاضرة المرفوعة بواسطة استاذ(ة) المادة . وقد تبدو لك غير متكاملة . حيث يضع استاذ المادة في بعض الاحيان فقط الجزء الاول من المحاضرة من اجل الاطلاع على ما ستقوم بتحميله لاحقا . في نظام التعليم الالكتروني نوفر هذه الخدمة لكي نبقيك على اطلاع حول محتوى الملف الذي ستقوم بتحميله .
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