Since the
surface energy term scales with c and the strain energy term scales with c2,
Utot has to go through a maximum at a certain critical crack size ccrit(Fig. F c). This is an important result since it implies that extending a crack that is
smaller than ccrit consumes rather than liberates energy and is thus
stable. In contrast, flaws that are longer than ccrit are unstable since
extending them releases more energy than is consumed. Note that increasing the
applied stress (Fig. F d) will result in failure at smaller critical
flaw sizes. For instance, a solid for which the size of the largest flaw lies
somewhere between those shown in Fig. F c and d will not fail at the
stress shown in Fig. F c, but will fail if that stress is increased
(Fig. F d).
The location of the maximum is determined by
differentiating Eq. (7) and equating it to zero. Carrying out the
differentiation, replacing ?app by ?f, and rearranging
terms, one can show that the condition for failure is